F(-2)=2x^2+5x+4

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Solution for F(-2)=2x^2+5x+4 equation: 



(-2)=2F^2+5F+4

We move all terms to the left:

(-2)-(2F^2+5F+4)=0

We add all the numbers together, and all the variables

-(2F^2+5F+4)-2=0

We get rid of parentheses

-2F^2-5F-4-2=0

We add all the numbers together, and all the variables

-2F^2-5F-6=0

a = -2; b = -5; c = -6;
Δ = b2-4ac
Δ = -52-4·(-2)·(-6)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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